Cats & Dogs #292: 10x10 Grid Puzzle (Hard)

hard

Tap a square: 🐱 cat → 🐶 dog → clear

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🐱 5 cats and 🐶 5 dogs in every row and column = same   × different

A 10x10 logic grid: 5 cats and 5 dogs in every row and column, no three of a kind in a row, and a few = and × clues to point the way.

  • Exactly 5 cats and 5 dogs in every row and every column.
  • Never three of the same animal in a row, across or down.
  • An = between two squares means the same animal; a × means different animals.

Step-by-step solution

Squares are written as R<row>C<column>, counting from the top-left.

  1. The × clue between R4C1 and R3C1 means they are different. R4C1 is a dog, so R3C1 is a cat.
  2. Imagine R3C5 were a dog: following the rules from there soon forces a contradiction, so R3C5 must be a cat.
  3. The = clue between R3C5 and R4C5 means they are the same. R3C5 is a cat, so R4C5 is a cat.
  4. R3C5 and R4C5 are both cats, so R2C5 must be a dog (no three in a row).
  5. R3C5 and R4C5 are both cats, so R5C5 must be a dog (no three in a row).
  6. Imagine R3C9 were a dog: following the rules from there soon forces a contradiction, so R3C9 must be a cat.
  7. The = clue between R3C9 and R4C9 means they are the same. R3C9 is a cat, so R4C9 is a cat.
  8. R4C8 and R4C9 are both cats, so R4C7 must be a dog (no three in a row).
  9. R4C8 and R4C9 are both cats, so R4C10 must be a dog (no three in a row).
  10. R3C9 and R4C9 are both cats, so R5C9 must be a dog (no three in a row).
  11. The × clue between R5C9 and R6C9 means they are different. R5C9 is a dog, so R6C9 is a cat.
  12. Imagine R3C6 were a cat: following the rules from there soon forces a contradiction, so R3C6 must be a dog.
  13. Imagine R2C10 were a dog: following the rules from there soon forces a contradiction, so R2C10 must be a cat.
  14. Imagine R3C7 were a dog: following the rules from there soon forces a contradiction, so R3C7 must be a cat.
  15. R3C7 and R3C9 are both cats with one square between them, so R3C8 must be a dog.
  16. Imagine R3C10 were a cat: following the rules from there soon forces a contradiction, so R3C10 must be a dog.
  17. R3C10 and R4C10 are both dogs, so R5C10 must be a cat (no three in a row).
  18. Imagine R4C6 were a dog: following the rules from there soon forces a contradiction, so R4C6 must be a cat.
  19. The = clue between R4C6 and R5C6 means they are the same. R4C6 is a cat, so R5C6 is a cat.
  20. The × clue between R5C6 and R5C7 means they are different. R5C6 is a cat, so R5C7 is a dog.
  21. R5C7 and R5C9 are both dogs with one square between them, so R5C8 must be a cat.
  22. R4C6 and R5C6 are both cats, so R6C6 must be a dog (no three in a row).
  23. R4C7 and R5C7 are both dogs, so R6C7 must be a cat (no three in a row).
  24. R6C7 and R6C9 are both cats with one square between them, so R6C8 must be a dog.
  25. Imagine R7C3 were a cat: following the rules from there soon forces a contradiction, so R7C3 must be a dog.
  26. Imagine R7C7 were a cat: following the rules from there soon forces a contradiction, so R7C7 must be a dog.
  27. The = clue between R7C7 and R8C7 means they are the same. R7C7 is a dog, so R8C7 is a dog.
  28. R7C7 and R8C7 are both dogs, so R9C7 must be a cat (no three in a row).
  29. Imagine R5C2 were a cat: following the rules from there soon forces a contradiction, so R5C2 must be a dog.
  30. The = clue between R5C2 and R6C2 means they are the same. R5C2 is a dog, so R6C2 is a dog.
  31. R5C2 and R6C2 are both dogs, so R4C2 must be a cat (no three in a row).
  32. The × clue between R4C2 and R4C3 means they are different. R4C2 is a cat, so R4C3 is a dog.
  33. R5C2 and R6C2 are both dogs, so R7C2 must be a cat (no three in a row).
  34. Imagine R7C8 were a dog: following the rules from there soon forces a contradiction, so R7C8 must be a cat.
  35. The = clue between R7C8 and R7C9 means they are the same. R7C8 is a cat, so R7C9 is a cat.
  36. R7C8 and R7C9 are both cats, so R7C10 must be a dog (no three in a row).
  37. R6C9 and R7C9 are both cats, so R8C9 must be a dog (no three in a row).
  38. The = clue between R8C9 and R8C10 means they are the same. R8C9 is a dog, so R8C10 is a dog.
  39. R8C7 and R8C9 are both dogs with one square between them, so R8C8 must be a cat.
  40. R7C8 and R8C8 are both cats, so R9C8 must be a dog (no three in a row).
  41. R7C10 and R8C10 are both dogs, so R6C10 must be a cat (no three in a row).
  42. R7C10 and R8C10 are both dogs, so R9C10 must be a cat (no three in a row).
  43. Imagine R1C7 were a cat: following the rules from there soon forces a contradiction, so R1C7 must be a dog.
  44. Column 7 already has its 5 dogs, so R2C7 and R10C7 must be cats.
  45. Imagine R1C8 were a dog: following the rules from there soon forces a contradiction, so R1C8 must be a cat.
  46. Column 8 already has its 5 cats, so R2C8 and R10C8 must be dogs.
  47. The = clue between R10C8 and R10C9 means they are the same. R10C8 is a dog, so R10C9 is a dog.
  48. R10C8 and R10C9 are both dogs, so R10C10 must be a cat (no three in a row).
  49. R8C9 and R10C9 are both dogs with one square between them, so R9C9 must be a cat.
  50. Column 9 already has its 5 cats, so R1C9 must be dogs.
  51. Column 10 already has its 5 cats, so R1C10 must be dogs.
  52. Imagine R2C2 were a cat: following the rules from there soon forces a contradiction, so R2C2 must be a dog.
  53. The × clue between R2C2 and R2C3 means they are different. R2C2 is a dog, so R2C3 is a cat.
  54. Imagine R1C2 were a dog: following the rules from there soon forces a contradiction, so R1C2 must be a cat.
  55. Imagine R3C2 were a cat: following the rules from there soon forces a contradiction, so R3C2 must be a dog.
  56. Column 2 already has its 5 dogs, so R9C2 and R10C2 must be cats.
  57. Imagine R3C3 were a cat: following the rules from there soon forces a contradiction, so R3C3 must be a dog.
  58. R3C2 and R3C3 are both dogs, so R3C4 must be a cat (no three in a row).
  59. Imagine R1C4 were a cat: following the rules from there soon forces a contradiction, so R1C4 must be a dog.
  60. Imagine R1C5 were a dog: following the rules from there soon forces a contradiction, so R1C5 must be a cat.
  61. Imagine R1C6 were a dog: following the rules from there soon forces a contradiction, so R1C6 must be a cat.
  62. Imagine R5C1 were a dog: following the rules from there soon forces a contradiction, so R5C1 must be a cat.
  63. Row 5 already has its 5 cats, so R5C4 must be dogs.
  64. R4C4 and R5C4 are both dogs, so R6C4 must be a cat (no three in a row).
  65. R6C4 and R7C4 are both cats, so R8C4 must be a dog (no three in a row).
  66. R8C2 and R8C4 are both dogs with one square between them, so R8C3 must be a cat.
  67. Row 8 already has its 5 dogs, so R8C1, R8C5 and R8C6 must be cats.
  68. Imagine R1C1 were a cat: following the rules from there soon forces a contradiction, so R1C1 must be a dog.
  69. Row 1 already has its 5 dogs, so R1C3 must be cats.
  70. Imagine R2C1 were a dog: following the rules from there soon forces a contradiction, so R2C1 must be a cat.
  71. Imagine R6C1 were a cat: following the rules from there soon forces a contradiction, so R6C1 must be a dog.
  72. R6C1 and R6C2 are both dogs, so R6C3 must be a cat (no three in a row).
  73. R6C3 and R6C4 are both cats, so R6C5 must be a dog (no three in a row).
  74. R5C5 and R6C5 are both dogs, so R7C5 must be a cat (no three in a row).
  75. R7C4 and R7C5 are both cats, so R7C6 must be a dog (no three in a row).
  76. R7C5 and R8C5 are both cats, so R9C5 must be a dog (no three in a row).
  77. Row 7 already has its 5 cats, so R7C1 must be dogs.
  78. Column 3 already has its 5 cats, so R9C3 must be dogs.
  79. R9C3 and R9C5 are both dogs with one square between them, so R9C4 must be a cat.
  80. Row 9 already has its 5 cats, so R9C1 must be dogs.
  81. The × clue between R9C1 and R10C1 means they are different. R9C1 is a dog, so R10C1 is a cat.
  82. R10C1 and R10C2 are both cats, so R10C3 must be a dog (no three in a row).
  83. Row 9 already has its 5 cats, so R9C6 must be dogs.
  84. Column 5 already has its 5 cats, so R10C5 must be dogs.
  85. R10C3 and R10C5 are both dogs with one square between them, so R10C4 must be a cat.
  86. Row 10 already has its 5 cats, so R10C6 must be dogs.
  87. Column 4 already has its 5 cats, so R2C4 must be dogs.
  88. R2C4 and R2C5 are both dogs, so R2C6 must be a cat (no three in a row).

About this puzzle

This 10×10 grid starts with 7 filled squares and 14 = / × clues. It can be solved in 88 steps using a "what if" trial of one square on top of the basic rules.

Count as you go. Once a row or column has all of one animal, every remaining empty square in it must be the other.

This kind of puzzle is known as a binary or Takuzu puzzle, here with cats and dogs and extra = / × clues.

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