Cats & Dogs #276: 10x10 Grid Puzzle (Hard)
hardTap a square: 🐱 cat → 🐶 dog → clear
🐱 5 cats and 🐶 5 dogs in every row and column
= same × different
Use pure logic to place every cat and dog. Each row and column holds 5 of each animal, three in a row is never allowed, and the clues between squares settle the rest.
- Exactly 5 cats and 5 dogs in every row and every column.
- Never three of the same animal in a row, across or down.
- An = between two squares means the same animal; a × means different animals.
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Step-by-step solution
Squares are written as R<row>C<column>, counting from the top-left.
- The × clue between R1C2 and R1C3 means they are different. R1C2 is a cat, so R1C3 is a dog.
- The = clue between R10C7 and R9C7 means they are the same. R10C7 is a cat, so R9C7 is a cat.
- R2C1 and R2C2 are both cats, so R2C3 must be a dog (no three in a row).
- The × clue between R2C3 and R2C4 means they are different. R2C3 is a dog, so R2C4 is a cat.
- R1C2 and R2C2 are both cats, so R3C2 must be a dog (no three in a row).
- R1C3 and R2C3 are both dogs, so R3C3 must be a cat (no three in a row).
- R9C7 and R10C7 are both cats, so R8C7 must be a dog (no three in a row).
- Imagine R2C6 were a cat: following the rules from there soon forces a contradiction, so R2C6 must be a dog.
- The = clue between R2C6 and R2C7 means they are the same. R2C6 is a dog, so R2C7 is a dog.
- R2C6 and R2C7 are both dogs, so R2C5 must be a cat (no three in a row).
- R2C6 and R2C7 are both dogs, so R2C8 must be a cat (no three in a row).
- Row 2 already has its 5 cats, so R2C9 must be dogs.
- The = clue between R2C9 and R1C9 means they are the same. R2C9 is a dog, so R1C9 is a dog.
- R1C9 and R2C9 are both dogs, so R3C9 must be a cat (no three in a row).
- Row 2 already has its 5 cats, so R2C10 must be dogs.
- The × clue between R2C10 and R3C10 means they are different. R2C10 is a dog, so R3C10 is a cat.
- R3C9 and R3C10 are both cats, so R3C8 must be a dog (no three in a row).
- Imagine R3C5 were a cat: following the rules from there soon forces a contradiction, so R3C5 must be a dog.
- Imagine R3C7 were a dog: following the rules from there soon forces a contradiction, so R3C7 must be a cat.
- Imagine R3C1 were a cat: following the rules from there soon forces a contradiction, so R3C1 must be a dog.
- Imagine R4C5 were a dog: following the rules from there soon forces a contradiction, so R4C5 must be a cat.
- The = clue between R4C5 and R4C6 means they are the same. R4C5 is a cat, so R4C6 is a cat.
- The × clue between R4C5 and R5C5 means they are different. R4C5 is a cat, so R5C5 is a dog.
- R4C5 and R4C6 are both cats, so R4C4 must be a dog (no three in a row).
- R4C5 and R4C6 are both cats, so R4C7 must be a dog (no three in a row).
- The = clue between R4C7 and R5C7 means they are the same. R4C7 is a dog, so R5C7 is a dog.
- R5C5 and R5C7 are both dogs with one square between them, so R5C6 must be a cat.
- R4C6 and R5C6 are both cats, so R3C6 must be a dog (no three in a row).
- R3C5 and R3C6 are both dogs, so R3C4 must be a cat (no three in a row).
- R2C4 and R3C4 are both cats, so R1C4 must be a dog (no three in a row).
- R1C3 and R1C4 are both dogs, so R1C5 must be a cat (no three in a row).
- R2C6 and R3C6 are both dogs, so R1C6 must be a cat (no three in a row).
- R1C5 and R1C6 are both cats, so R1C7 must be a dog (no three in a row).
- R1C7 and R1C9 are both dogs with one square between them, so R1C8 must be a cat.
- R4C6 and R5C6 are both cats, so R6C6 must be a dog (no three in a row).
- The × clue between R6C6 and R6C5 means they are different. R6C6 is a dog, so R6C5 is a cat.
- R6C6 and R6C8 are both dogs with one square between them, so R6C7 must be a cat.
- Column 7 already has its 5 dogs, so R7C7 must be cats.
- The × clue between R7C7 and R7C8 means they are different. R7C7 is a cat, so R7C8 is a dog.
- R6C8 and R7C8 are both dogs, so R5C8 must be a cat (no three in a row).
- The × clue between R5C8 and R4C8 means they are different. R5C8 is a cat, so R4C8 is a dog.
- R4C7 and R4C8 are both dogs, so R4C9 must be a cat (no three in a row).
- R6C8 and R7C8 are both dogs, so R8C8 must be a cat (no three in a row).
- R3C9 and R4C9 are both cats, so R5C9 must be a dog (no three in a row).
- The = clue between R5C9 and R6C9 means they are the same. R5C9 is a dog, so R6C9 is a dog.
- R6C8 and R6C9 are both dogs, so R6C10 must be a cat (no three in a row).
- R5C9 and R6C9 are both dogs, so R7C9 must be a cat (no three in a row).
- Imagine R7C3 were a dog: following the rules from there soon forces a contradiction, so R7C3 must be a cat.
- Imagine R7C5 were a cat: following the rules from there soon forces a contradiction, so R7C5 must be a dog.
- Imagine R8C9 were a dog: following the rules from there soon forces a contradiction, so R8C9 must be a cat.
- R8C8 and R8C9 are both cats, so R8C10 must be a dog (no three in a row).
- R7C9 and R8C9 are both cats, so R9C9 must be a dog (no three in a row).
- Column 9 already has its 5 dogs, so R10C9 must be cats.
- R10C7 and R10C9 are both cats with one square between them, so R10C8 must be a dog.
- Column 8 already has its 5 dogs, so R9C8 must be cats.
- R9C7 and R9C8 are both cats, so R9C6 must be a dog (no three in a row).
- Imagine R9C2 were a dog: following the rules from there soon forces a contradiction, so R9C2 must be a cat.
- Imagine R5C2 were a dog: following the rules from there soon forces a contradiction, so R5C2 must be a cat.
- The = clue between R5C2 and R6C2 means they are the same. R5C2 is a cat, so R6C2 is a cat.
- R5C2 and R6C2 are both cats, so R4C2 must be a dog (no three in a row).
- R4C2 and R4C4 are both dogs with one square between them, so R4C3 must be a cat.
- R5C2 and R6C2 are both cats, so R7C2 must be a dog (no three in a row).
- R3C3 and R4C3 are both cats, so R5C3 must be a dog (no three in a row).
- R5C3 and R5C5 are both dogs with one square between them, so R5C4 must be a cat.
- Column 2 already has its 5 cats, so R8C2 must be dogs.
- The = clue between R8C2 and R8C3 means they are the same. R8C2 is a dog, so R8C3 is a dog.
- R8C2 and R8C3 are both dogs, so R8C1 must be a cat (no three in a row).
- R8C2 and R8C3 are both dogs, so R8C4 must be a cat (no three in a row).
- Column 3 already has its 5 dogs, so R9C3 must be cats.
- R9C2 and R9C3 are both cats, so R9C4 must be a dog (no three in a row).
- R9C4 and R9C6 are both dogs with one square between them, so R9C5 must be a cat.
- Row 9 already has its 5 cats, so R9C10 must be dogs.
- R8C10 and R9C10 are both dogs, so R7C10 must be a cat (no three in a row).
- R6C10 and R7C10 are both cats, so R5C10 must be a dog (no three in a row).
- R8C10 and R9C10 are both dogs, so R10C10 must be a cat (no three in a row).
- Row 5 already has its 5 dogs, so R5C1 must be cats.
- Column 3 already has its 5 dogs, so R10C3 must be cats.
- Column 5 already has its 5 cats, so R8C5 must be dogs.
- R8C5 and R8C7 are both dogs with one square between them, so R8C6 must be a cat.
- The × clue between R8C6 and R7C6 means they are different. R8C6 is a cat, so R7C6 is a dog.
- R7C5 and R7C6 are both dogs, so R7C4 must be a cat (no three in a row).
- R5C4 and R7C4 are both cats with one square between them, so R6C4 must be a dog.
- Row 6 already has its 5 dogs, so R6C1 must be cats.
- R5C1 and R6C1 are both cats, so R4C1 must be a dog (no three in a row).
- R5C1 and R6C1 are both cats, so R7C1 must be a dog (no three in a row).
- Row 4 already has its 5 dogs, so R4C10 must be cats.
- Column 4 already has its 5 cats, so R10C4 must be dogs.
- Column 5 already has its 5 cats, so R10C5 must be dogs.
- R10C4 and R10C5 are both dogs, so R10C6 must be a cat (no three in a row).
- Row 10 already has its 5 cats, so R10C1 must be dogs.
- Column 1 already has its 5 dogs, so R1C1 must be cats.
- Row 1 already has its 5 cats, so R1C10 must be dogs.
About this puzzle
This 10×10 grid starts with 8 filled squares and 16 = / × clues. It can be solved in 92 steps using a "what if" trial of one square on top of the basic rules.
Whenever two of the same animal sit side by side, the squares on both ends must be the other animal. Look for these pairs first.
This kind of puzzle is known as a binary or Takuzu puzzle, here with cats and dogs and extra = / × clues.