Cats & Dogs #250: 10x10 Grid Puzzle (Hard)

hard

Tap a square: 🐱 cat → 🐶 dog → clear

0 / 100 · 0:00
🐱 5 cats and 🐶 5 dogs in every row and column = same   × different

A 10x10 logic grid: 5 cats and 5 dogs in every row and column, no three of a kind in a row, and a few = and × clues to point the way.

  • Exactly 5 cats and 5 dogs in every row and every column.
  • Never three of the same animal in a row, across or down.
  • An = between two squares means the same animal; a × means different animals.

Step-by-step solution

Squares are written as R<row>C<column>, counting from the top-left.

  1. The = clue between R6C5 and R5C5 means they are the same. R6C5 is a cat, so R5C5 is a cat.
  2. The = clue between R5C5 and R5C6 means they are the same. R5C5 is a cat, so R5C6 is a cat.
  3. R5C5 and R5C6 are both cats, so R5C4 must be a dog (no three in a row).
  4. R5C5 and R5C6 are both cats, so R5C7 must be a dog (no three in a row).
  5. The = clue between R5C7 and R6C7 means they are the same. R5C7 is a dog, so R6C7 is a dog.
  6. R8C3 and R8C5 are both cats with one square between them, so R8C4 must be a dog.
  7. R5C5 and R6C5 are both cats, so R4C5 must be a dog (no three in a row).
  8. R5C5 and R6C5 are both cats, so R7C5 must be a dog (no three in a row).
  9. R5C7 and R6C7 are both dogs, so R4C7 must be a cat (no three in a row).
  10. R5C7 and R6C7 are both dogs, so R7C7 must be a cat (no three in a row).
  11. R7C8 and R8C8 are both dogs, so R6C8 must be a cat (no three in a row).
  12. R5C8 and R6C8 are both cats, so R4C8 must be a dog (no three in a row).
  13. The × clue between R4C8 and R3C8 means they are different. R4C8 is a dog, so R3C8 is a cat.
  14. The × clue between R4C8 and R4C9 means they are different. R4C8 is a dog, so R4C9 is a cat.
  15. R7C8 and R8C8 are both dogs, so R9C8 must be a cat (no three in a row).
  16. Imagine R1C8 were a cat: following the rules from there soon forces a contradiction, so R1C8 must be a dog.
  17. Imagine R2C8 were a cat: following the rules from there soon forces a contradiction, so R2C8 must be a dog.
  18. R2C8 and R2C10 are both dogs with one square between them, so R2C9 must be a cat.
  19. R2C9 and R4C9 are both cats with one square between them, so R3C9 must be a dog.
  20. Column 8 already has its 5 dogs, so R10C8 must be cats.
  21. The = clue between R10C8 and R10C9 means they are the same. R10C8 is a cat, so R10C9 is a cat.
  22. R10C8 and R10C9 are both cats, so R10C7 must be a dog (no three in a row).
  23. Imagine R3C1 were a dog: following the rules from there soon forces a contradiction, so R3C1 must be a cat.
  24. The = clue between R3C1 and R4C1 means they are the same. R3C1 is a cat, so R4C1 is a cat.
  25. The = clue between R4C1 and R4C2 means they are the same. R4C1 is a cat, so R4C2 is a cat.
  26. R4C1 and R4C2 are both cats, so R4C3 must be a dog (no three in a row).
  27. R4C3 and R4C5 are both dogs with one square between them, so R4C4 must be a cat.
  28. R3C1 and R4C1 are both cats, so R2C1 must be a dog (no three in a row).
  29. R3C1 and R4C1 are both cats, so R5C1 must be a dog (no three in a row).
  30. R3C3 and R4C3 are both dogs, so R2C3 must be a cat (no three in a row).
  31. R3C3 and R4C3 are both dogs, so R5C3 must be a cat (no three in a row).
  32. Row 4 already has its 5 cats, so R4C6 and R4C10 must be dogs.
  33. R2C10 and R4C10 are both dogs with one square between them, so R3C10 must be a cat.
  34. R4C10 and R6C10 are both dogs with one square between them, so R5C10 must be a cat.
  35. R5C8 and R5C10 are both cats with one square between them, so R5C9 must be a dog.
  36. Row 5 already has its 5 cats, so R5C2 must be dogs.
  37. Imagine R1C10 were a dog: following the rules from there soon forces a contradiction, so R1C10 must be a cat.
  38. Imagine R6C1 were a dog: following the rules from there soon forces a contradiction, so R6C1 must be a cat.
  39. The = clue between R6C1 and R6C2 means they are the same. R6C1 is a cat, so R6C2 is a cat.
  40. R6C1 and R6C2 are both cats, so R6C3 must be a dog (no three in a row).
  41. R6C1 and R7C1 are both cats, so R8C1 must be a dog (no three in a row).
  42. Imagine R1C1 were a cat: following the rules from there soon forces a contradiction, so R1C1 must be a dog.
  43. Imagine R7C2 were a cat: following the rules from there soon forces a contradiction, so R7C2 must be a dog.
  44. Imagine R7C3 were a dog: following the rules from there soon forces a contradiction, so R7C3 must be a cat.
  45. The = clue between R7C3 and R7C4 means they are the same. R7C3 is a cat, so R7C4 is a cat.
  46. R7C3 and R8C3 are both cats, so R9C3 must be a dog (no three in a row).
  47. Imagine R1C3 were a dog: following the rules from there soon forces a contradiction, so R1C3 must be a cat.
  48. Column 3 already has its 5 cats, so R10C3 must be dogs.
  49. Imagine R6C4 were a cat: following the rules from there soon forces a contradiction, so R6C4 must be a dog.
  50. Imagine R7C6 were a cat: following the rules from there soon forces a contradiction, so R7C6 must be a dog.
  51. Imagine R8C2 were a cat: following the rules from there soon forces a contradiction, so R8C2 must be a dog.
  52. R7C2 and R8C2 are both dogs, so R9C2 must be a cat (no three in a row).
  53. The = clue between R9C2 and R9C1 means they are the same. R9C2 is a cat, so R9C1 is a cat.
  54. Column 1 already has its 5 cats, so R10C1 must be dogs.
  55. Imagine R1C2 were a cat: following the rules from there soon forces a contradiction, so R1C2 must be a dog.
  56. Imagine R8C6 were a dog: following the rules from there soon forces a contradiction, so R8C6 must be a cat.
  57. R8C5 and R8C6 are both cats, so R8C7 must be a dog (no three in a row).
  58. R8C7 and R8C8 are both dogs, so R8C9 must be a cat (no three in a row).
  59. R8C7 and R10C7 are both dogs with one square between them, so R9C7 must be a cat.
  60. R9C7 and R9C8 are both cats, so R9C6 must be a dog (no three in a row).
  61. R9C7 and R9C8 are both cats, so R9C9 must be a dog (no three in a row).
  62. Row 8 already has its 5 dogs, so R8C10 must be cats.
  63. Imagine R1C5 were a cat: following the rules from there soon forces a contradiction, so R1C5 must be a dog.
  64. The = clue between R1C5 and R2C5 means they are the same. R1C5 is a dog, so R2C5 is a dog.
  65. The × clue between R2C5 and R2C4 means they are different. R2C5 is a dog, so R2C4 is a cat.
  66. R2C3 and R2C4 are both cats, so R2C2 must be a dog (no three in a row).
  67. R1C2 and R2C2 are both dogs, so R3C2 must be a cat (no three in a row).
  68. R2C4 and R4C4 are both cats with one square between them, so R3C4 must be a dog.
  69. R3C3 and R3C4 are both dogs, so R3C5 must be a cat (no three in a row).
  70. Row 2 already has its 5 dogs, so R2C6 and R2C7 must be cats.
  71. R2C7 and R4C7 are both cats with one square between them, so R3C7 must be a dog.
  72. Row 3 already has its 5 cats, so R3C6 must be dogs.
  73. Column 7 already has its 5 dogs, so R1C7 must be cats.
  74. Imagine R1C4 were a dog: following the rules from there soon forces a contradiction, so R1C4 must be a cat.
  75. Imagine R1C6 were a dog: following the rules from there soon forces a contradiction, so R1C6 must be a cat.
  76. Row 1 already has its 5 cats, so R1C9 must be dogs.
  77. Imagine R6C6 were a cat: following the rules from there soon forces a contradiction, so R6C6 must be a dog.
  78. Row 6 already has its 5 dogs, so R6C9 must be cats.
  79. R6C9 and R8C9 are both cats with one square between them, so R7C9 must be a dog.
  80. R7C8 and R7C9 are both dogs, so R7C10 must be a cat (no three in a row).
  81. R7C10 and R8C10 are both cats, so R9C10 must be a dog (no three in a row).
  82. Column 6 already has its 5 dogs, so R10C6 must be cats.
  83. The × clue between R10C6 and R10C5 means they are different. R10C6 is a cat, so R10C5 is a dog.
  84. R10C3 and R10C5 are both dogs with one square between them, so R10C4 must be a cat.
  85. Column 4 already has its 5 cats, so R9C4 must be dogs.
  86. R9C3 and R9C4 are both dogs, so R9C5 must be a cat (no three in a row).

About this puzzle

This 10×10 grid starts with 12 filled squares and 14 = / × clues. It can be solved in 86 steps using a "what if" trial of one square on top of the basic rules.

Count as you go. Once a row or column has all of one animal, every remaining empty square in it must be the other.

This kind of puzzle is known as a binary or Takuzu puzzle, here with cats and dogs and extra = / × clues.

More hard puzzles