Cats & Dogs #215: 10x10 Grid Puzzle (Hard)

hard

Tap a square: 🐱 cat → 🐶 dog → clear

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🐱 5 cats and 🐶 5 dogs in every row and column = same   × different

A 10x10 logic grid: 5 cats and 5 dogs in every row and column, no three of a kind in a row, and a few = and × clues to point the way.

  • Exactly 5 cats and 5 dogs in every row and every column.
  • Never three of the same animal in a row, across or down.
  • An = between two squares means the same animal; a × means different animals.

Step-by-step solution

Squares are written as R<row>C<column>, counting from the top-left.

  1. The = clue between R4C5 and R3C5 means they are the same. R4C5 is a cat, so R3C5 is a cat.
  2. The = clue between R3C5 and R3C6 means they are the same. R3C5 is a cat, so R3C6 is a cat.
  3. The = clue between R10C10 and R9C10 means they are the same. R10C10 is a dog, so R9C10 is a dog.
  4. R3C3 and R3C5 are both cats with one square between them, so R3C4 must be a dog.
  5. R3C5 and R3C6 are both cats, so R3C7 must be a dog (no three in a row).
  6. The = clue between R3C7 and R2C7 means they are the same. R3C7 is a dog, so R2C7 is a dog.
  7. R4C3 and R4C5 are both cats with one square between them, so R4C4 must be a dog.
  8. R3C3 and R4C3 are both cats, so R2C3 must be a dog (no three in a row).
  9. The × clue between R2C3 and R1C3 means they are different. R2C3 is a dog, so R1C3 is a cat.
  10. R3C3 and R4C3 are both cats, so R5C3 must be a dog (no three in a row).
  11. R3C4 and R4C4 are both dogs, so R2C4 must be a cat (no three in a row).
  12. R3C4 and R4C4 are both dogs, so R5C4 must be a cat (no three in a row).
  13. R3C5 and R4C5 are both cats, so R2C5 must be a dog (no three in a row).
  14. R2C5 and R2C7 are both dogs with one square between them, so R2C6 must be a cat.
  15. R3C5 and R4C5 are both cats, so R5C5 must be a dog (no three in a row).
  16. R5C5 and R5C6 are both dogs, so R5C7 must be a cat (no three in a row).
  17. R2C6 and R3C6 are both cats, so R1C6 must be a dog (no three in a row).
  18. R2C6 and R3C6 are both cats, so R4C6 must be a dog (no three in a row).
  19. R4C6 and R5C6 are both dogs, so R6C6 must be a cat (no three in a row).
  20. R2C7 and R3C7 are both dogs, so R1C7 must be a cat (no three in a row).
  21. R2C7 and R3C7 are both dogs, so R4C7 must be a cat (no three in a row).
  22. R4C7 and R5C7 are both cats, so R6C7 must be a dog (no three in a row).
  23. R9C10 and R10C10 are both dogs, so R8C10 must be a cat (no three in a row).
  24. Imagine R6C4 were a cat: following the rules from there soon forces a contradiction, so R6C4 must be a dog.
  25. Imagine R6C10 were a cat: following the rules from there soon forces a contradiction, so R6C10 must be a dog.
  26. The = clue between R6C10 and R7C10 means they are the same. R6C10 is a dog, so R7C10 is a dog.
  27. R6C10 and R7C10 are both dogs, so R5C10 must be a cat (no three in a row).
  28. The = clue between R5C10 and R5C9 means they are the same. R5C10 is a cat, so R5C9 is a cat.
  29. R5C7 and R5C9 are both cats with one square between them, so R5C8 must be a dog.
  30. The = clue between R5C8 and R4C8 means they are the same. R5C8 is a dog, so R4C8 is a dog.
  31. R4C8 and R5C8 are both dogs, so R3C8 must be a cat (no three in a row).
  32. R4C8 and R5C8 are both dogs, so R6C8 must be a cat (no three in a row).
  33. Imagine R1C8 were a cat: following the rules from there soon forces a contradiction, so R1C8 must be a dog.
  34. Imagine R1C10 were a dog: following the rules from there soon forces a contradiction, so R1C10 must be a cat.
  35. Imagine R2C10 were a dog: following the rules from there soon forces a contradiction, so R2C10 must be a cat.
  36. R1C10 and R2C10 are both cats, so R3C10 must be a dog (no three in a row).
  37. Column 10 already has its 5 dogs, so R4C10 must be cats.
  38. Imagine R6C9 were a cat: following the rules from there soon forces a contradiction, so R6C9 must be a dog.
  39. The = clue between R6C9 and R7C9 means they are the same. R6C9 is a dog, so R7C9 is a dog.
  40. R7C9 and R7C10 are both dogs, so R7C8 must be a cat (no three in a row).
  41. R6C8 and R7C8 are both cats, so R8C8 must be a dog (no three in a row).
  42. R6C9 and R7C9 are both dogs, so R8C9 must be a cat (no three in a row).
  43. Imagine R6C5 were a dog: following the rules from there soon forces a contradiction, so R6C5 must be a cat.
  44. Imagine R7C4 were a dog: following the rules from there soon forces a contradiction, so R7C4 must be a cat.
  45. The = clue between R7C4 and R7C5 means they are the same. R7C4 is a cat, so R7C5 is a cat.
  46. R7C4 and R7C5 are both cats, so R7C3 must be a dog (no three in a row).
  47. R7C4 and R7C5 are both cats, so R7C6 must be a dog (no three in a row).
  48. R5C3 and R7C3 are both dogs with one square between them, so R6C3 must be a cat.
  49. R6C5 and R7C5 are both cats, so R8C5 must be a dog (no three in a row).
  50. Imagine R1C2 were a cat: following the rules from there soon forces a contradiction, so R1C2 must be a dog.
  51. Imagine R1C4 were a dog: following the rules from there soon forces a contradiction, so R1C4 must be a cat.
  52. R1C3 and R1C4 are both cats, so R1C5 must be a dog (no three in a row).
  53. Row 1 already has its 5 dogs, so R1C9 must be cats.
  54. Imagine R2C8 were a dog: following the rules from there soon forces a contradiction, so R2C8 must be a cat.
  55. R2C8 and R2C10 are both cats with one square between them, so R2C9 must be a dog.
  56. The = clue between R2C9 and R3C9 means they are the same. R2C9 is a dog, so R3C9 is a dog.
  57. R2C9 and R3C9 are both dogs, so R4C9 must be a cat (no three in a row).
  58. Row 4 already has its 5 cats, so R4C1 and R4C2 must be dogs.
  59. Imagine R7C1 were a dog: following the rules from there soon forces a contradiction, so R7C1 must be a cat.
  60. Imagine R8C2 were a dog: following the rules from there soon forces a contradiction, so R8C2 must be a cat.
  61. Imagine R2C1 were a cat: following the rules from there soon forces a contradiction, so R2C1 must be a dog.
  62. R2C1 and R2C3 are both dogs with one square between them, so R2C2 must be a cat.
  63. R1C1 and R2C1 are both dogs, so R3C1 must be a cat (no three in a row).
  64. R3C1 and R3C3 are both cats with one square between them, so R3C2 must be a dog.
  65. R3C2 and R4C2 are both dogs, so R5C2 must be a cat (no three in a row).
  66. Row 5 already has its 5 cats, so R5C1 must be dogs.
  67. R4C1 and R5C1 are both dogs, so R6C1 must be a cat (no three in a row).
  68. R6C1 and R6C3 are both cats with one square between them, so R6C2 must be a dog.
  69. Column 1 already has its 5 dogs, so R9C1 and R10C1 must be cats.
  70. Imagine R7C2 were a dog: following the rules from there soon forces a contradiction, so R7C2 must be a cat.
  71. R7C2 and R8C2 are both cats, so R9C2 must be a dog (no three in a row).
  72. Row 7 already has its 5 cats, so R7C7 must be dogs.
  73. R6C7 and R7C7 are both dogs, so R8C7 must be a cat (no three in a row).
  74. Column 2 already has its 5 dogs, so R10C2 must be cats.
  75. R10C1 and R10C2 are both cats, so R10C3 must be a dog (no three in a row).
  76. The × clue between R10C3 and R9C3 means they are different. R10C3 is a dog, so R9C3 is a cat.
  77. Column 3 already has its 5 cats, so R8C3 must be dogs.
  78. R8C3 and R8C5 are both dogs with one square between them, so R8C4 must be a cat.
  79. R7C4 and R8C4 are both cats, so R9C4 must be a dog (no three in a row).
  80. Row 8 already has its 5 cats, so R8C6 must be dogs.
  81. R7C6 and R8C6 are both dogs, so R9C6 must be a cat (no three in a row).
  82. Column 4 already has its 5 cats, so R10C4 must be dogs.
  83. R10C3 and R10C4 are both dogs, so R10C5 must be a cat (no three in a row).
  84. Column 5 already has its 5 cats, so R9C5 must be dogs.
  85. Column 6 already has its 5 dogs, so R10C6 must be cats.
  86. R10C5 and R10C6 are both cats, so R10C7 must be a dog (no three in a row).
  87. Column 7 already has its 5 dogs, so R9C7 must be cats.
  88. R9C6 and R9C7 are both cats, so R9C8 must be a dog (no three in a row).
  89. R9C8 and R9C10 are both dogs with one square between them, so R9C9 must be a cat.
  90. R8C8 and R9C8 are both dogs, so R10C8 must be a cat (no three in a row).
  91. R8C9 and R9C9 are both cats, so R10C9 must be a dog (no three in a row).

About this puzzle

This 10×10 grid starts with 7 filled squares and 12 = / × clues. It can be solved in 91 steps using a "what if" trial of one square on top of the basic rules.

Count as you go. Once a row or column has all of one animal, every remaining empty square in it must be the other.

This kind of puzzle is known as a binary or Takuzu puzzle, here with cats and dogs and extra = / × clues.

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