Cats & Dogs #284: 10x10 Grid Puzzle (Hard)

hard

Tap a square: 🐱 cat → 🐶 dog → clear

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🐱 5 cats and 🐶 5 dogs in every row and column = same   × different

A 10x10 logic grid: 5 cats and 5 dogs in every row and column, no three of a kind in a row, and a few = and × clues to point the way.

  • Exactly 5 cats and 5 dogs in every row and every column.
  • Never three of the same animal in a row, across or down.
  • An = between two squares means the same animal; a × means different animals.

Step-by-step solution

Squares are written as R<row>C<column>, counting from the top-left.

  1. The = clue between R1C7 and R1C6 means they are the same. R1C7 is a dog, so R1C6 is a dog.
  2. The = clue between R8C4 and R9C4 means they are the same. R8C4 is a dog, so R9C4 is a dog.
  3. R1C6 and R1C7 are both dogs, so R1C5 must be a cat (no three in a row).
  4. R1C6 and R1C7 are both dogs, so R1C8 must be a cat (no three in a row).
  5. R8C4 and R9C4 are both dogs, so R7C4 must be a cat (no three in a row).
  6. R8C4 and R9C4 are both dogs, so R10C4 must be a cat (no three in a row).
  7. R7C8 and R9C8 are both cats with one square between them, so R8C8 must be a dog.
  8. Imagine R2C8 were a cat: following the rules from there soon forces a contradiction, so R2C8 must be a dog.
  9. Imagine R3C8 were a cat: following the rules from there soon forces a contradiction, so R3C8 must be a dog.
  10. R2C8 and R3C8 are both dogs, so R4C8 must be a cat (no three in a row).
  11. Column 8 already has its 5 cats, so R5C8 and R6C8 must be dogs.
  12. The × clue between R6C8 and R6C7 means they are different. R6C8 is a dog, so R6C7 is a cat.
  13. Imagine R10C2 were a cat: following the rules from there soon forces a contradiction, so R10C2 must be a dog.
  14. The = clue between R10C2 and R10C3 means they are the same. R10C2 is a dog, so R10C3 is a dog.
  15. R10C2 and R10C3 are both dogs, so R10C1 must be a cat (no three in a row).
  16. R8C1 and R10C1 are both cats with one square between them, so R9C1 must be a dog.
  17. Imagine R2C3 were a dog: following the rules from there soon forces a contradiction, so R2C3 must be a cat.
  18. The = clue between R2C3 and R2C4 means they are the same. R2C3 is a cat, so R2C4 is a cat.
  19. R2C3 and R2C4 are both cats, so R2C2 must be a dog (no three in a row).
  20. The × clue between R2C2 and R3C2 means they are different. R2C2 is a dog, so R3C2 is a cat.
  21. The × clue between R3C2 and R4C2 means they are different. R3C2 is a cat, so R4C2 is a dog.
  22. R2C3 and R2C4 are both cats, so R2C5 must be a dog (no three in a row).
  23. Imagine R1C4 were a cat: following the rules from there soon forces a contradiction, so R1C4 must be a dog.
  24. Imagine R3C3 were a cat: following the rules from there soon forces a contradiction, so R3C3 must be a dog.
  25. Imagine R3C4 were a dog: following the rules from there soon forces a contradiction, so R3C4 must be a cat.
  26. The = clue between R3C4 and R3C5 means they are the same. R3C4 is a cat, so R3C5 is a cat.
  27. R3C4 and R3C5 are both cats, so R3C6 must be a dog (no three in a row).
  28. R3C6 and R3C8 are both dogs with one square between them, so R3C7 must be a cat.
  29. The = clue between R3C7 and R4C7 means they are the same. R3C7 is a cat, so R4C7 is a cat.
  30. R4C7 and R4C8 are both cats, so R4C6 must be a dog (no three in a row).
  31. R4C7 and R4C8 are both cats, so R4C9 must be a dog (no three in a row).
  32. R2C4 and R3C4 are both cats, so R4C4 must be a dog (no three in a row).
  33. R4C2 and R4C4 are both dogs with one square between them, so R4C3 must be a cat.
  34. R4C4 and R4C6 are both dogs with one square between them, so R4C5 must be a cat.
  35. R3C5 and R4C5 are both cats, so R5C5 must be a dog (no three in a row).
  36. R1C6 and R3C6 are both dogs with one square between them, so R2C6 must be a cat.
  37. R3C6 and R4C6 are both dogs, so R5C6 must be a cat (no three in a row).
  38. R3C7 and R4C7 are both cats, so R2C7 must be a dog (no three in a row).
  39. R2C7 and R2C8 are both dogs, so R2C9 must be a cat (no three in a row).
  40. R3C7 and R4C7 are both cats, so R5C7 must be a dog (no three in a row).
  41. R5C7 and R5C8 are both dogs, so R5C9 must be a cat (no three in a row).
  42. Imagine R3C1 were a cat: following the rules from there soon forces a contradiction, so R3C1 must be a dog.
  43. Imagine R4C1 were a dog: following the rules from there soon forces a contradiction, so R4C1 must be a cat.
  44. The = clue between R4C1 and R5C1 means they are the same. R4C1 is a cat, so R5C1 is a cat.
  45. The = clue between R5C1 and R5C2 means they are the same. R5C1 is a cat, so R5C2 is a cat.
  46. R5C1 and R5C2 are both cats, so R5C3 must be a dog (no three in a row).
  47. R5C3 and R5C5 are both dogs with one square between them, so R5C4 must be a cat.
  48. R4C1 and R5C1 are both cats, so R6C1 must be a dog (no three in a row).
  49. R5C3 and R7C3 are both dogs with one square between them, so R6C3 must be a cat.
  50. R5C4 and R7C4 are both cats with one square between them, so R6C4 must be a dog.
  51. The × clue between R6C4 and R6C5 means they are different. R6C4 is a dog, so R6C5 is a cat.
  52. R6C5 and R6C7 are both cats with one square between them, so R6C6 must be a dog.
  53. Row 4 already has its 5 cats, so R4C10 must be dogs.
  54. Row 5 already has its 5 cats, so R5C10 must be dogs.
  55. R4C10 and R5C10 are both dogs, so R3C10 must be a cat (no three in a row).
  56. R4C10 and R5C10 are both dogs, so R6C10 must be a cat (no three in a row).
  57. Row 3 already has its 5 cats, so R3C9 must be dogs.
  58. Imagine R1C3 were a dog: following the rules from there soon forces a contradiction, so R1C3 must be a cat.
  59. Imagine R1C1 were a cat: following the rules from there soon forces a contradiction, so R1C1 must be a dog.
  60. R1C1 and R3C1 are both dogs with one square between them, so R2C1 must be a cat.
  61. Row 2 already has its 5 cats, so R2C10 must be dogs.
  62. Column 1 already has its 5 cats, so R7C1 must be dogs.
  63. R7C1 and R7C3 are both dogs with one square between them, so R7C2 must be a cat.
  64. R5C2 and R7C2 are both cats with one square between them, so R6C2 must be a dog.
  65. Row 6 already has its 5 dogs, so R6C9 must be cats.
  66. R5C9 and R6C9 are both cats, so R7C9 must be a dog (no three in a row).
  67. Imagine R1C2 were a dog: following the rules from there soon forces a contradiction, so R1C2 must be a cat.
  68. Imagine R7C5 were a cat: following the rules from there soon forces a contradiction, so R7C5 must be a dog.
  69. Imagine R7C6 were a dog: following the rules from there soon forces a contradiction, so R7C6 must be a cat.
  70. R7C6 and R7C8 are both cats with one square between them, so R7C7 must be a dog.
  71. Row 7 already has its 5 dogs, so R7C10 must be cats.
  72. R6C10 and R7C10 are both cats, so R8C10 must be a dog (no three in a row).
  73. R8C8 and R8C10 are both dogs with one square between them, so R8C9 must be a cat.
  74. Imagine R1C9 were a dog: following the rules from there soon forces a contradiction, so R1C9 must be a cat.
  75. R1C8 and R1C9 are both cats, so R1C10 must be a dog (no three in a row).
  76. Column 9 already has its 5 cats, so R9C9 must be dogs.
  77. Column 10 already has its 5 dogs, so R9C10 and R10C10 must be cats.
  78. Imagine R8C2 were a cat: following the rules from there soon forces a contradiction, so R8C2 must be a dog.
  79. R8C2 and R8C4 are both dogs with one square between them, so R8C3 must be a cat.
  80. R8C2 and R10C2 are both dogs with one square between them, so R9C2 must be a cat.
  81. The × clue between R9C2 and R9C3 means they are different. R9C2 is a cat, so R9C3 is a dog.
  82. R9C3 and R9C4 are both dogs, so R9C5 must be a cat (no three in a row).
  83. Column 5 already has its 5 cats, so R8C5 must be dogs.
  84. R8C4 and R8C5 are both dogs, so R8C6 must be a cat (no three in a row).
  85. R7C6 and R8C6 are both cats, so R9C6 must be a dog (no three in a row).
  86. Row 8 already has its 5 dogs, so R8C7 must be cats.
  87. Row 9 already has its 5 dogs, so R9C7 must be cats.
  88. R8C7 and R9C7 are both cats, so R10C7 must be a dog (no three in a row).
  89. Column 5 already has its 5 cats, so R10C5 must be dogs.
  90. R10C5 and R10C7 are both dogs with one square between them, so R10C6 must be a cat.

About this puzzle

This 10×10 grid starts with 8 filled squares and 13 = / × clues. It can be solved in 90 steps using a "what if" trial of one square on top of the basic rules.

Count as you go. Once a row or column has all of one animal, every remaining empty square in it must be the other.

This kind of puzzle is known as a binary or Takuzu puzzle, here with cats and dogs and extra = / × clues.

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